Given a binary tree, return the_preorder_traversal of its nodes' values.
Input: [1,null,2,3]
1
\
2
/
3
Output: [1,2,3]
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> list = new ArrayList<>();
preorder(root, list);
return list;
}
public void preorder(TreeNode node, List<Integer> list) {
if (node == null) return;
list.add(node.val);
preorder(node.left, list);
preorder(node.right, list);
}
}