Given an n-ary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example, given a3-arytree:
We should return its level order traversal:
[
[1],
[3,2,4],
[5,6]
]
Solution
/*
// Definition for a Node.
class Node {
public int val;
public List<Node> children;
public Node() {}
public Node(int _val,List<Node> _children) {
val = _val;
children = _children;
}
};
*/
class Solution {
public List<List<Integer>> levelOrder(Node root) {
return traverse(root);
}
private List<List<Integer>> traverse(Node node) {
List<List<Integer>> result = new ArrayList<>();
if (node == null) return result;
Queue<Node> queue = new LinkedList<>();
queue.offer(node);
while (!queue.isEmpty()) {
int size = queue.size();
List<Integer> subList = new ArrayList<>();
for (int i = 0; i < size; i++) {
Node current = queue.poll();
subList.add(current.val);
if (current.children != null) {
for (Node child : current.children) {
queue.offer(child);
}
}
}
result.add(subList);
}
return result;
}
}