Given an n-ary tree, return thepreordertraversal of its nodes' values. For example, given a3-arytree:
Return its preorder traversal as:[1,3,5,6,2,4].
Note: Recursive solution is trivial, could you do it iteratively?
Solution
/*
// Definition for a Node.
class Node {
public int val;
public List<Node> children;
public Node() {}
public Node(int _val,List<Node> _children) {
val = _val;
children = _children;
}
};
*/
class Solution {
public List<Integer> preorder(Node root) {
List<Integer> result = new ArrayList<>();
traverse(root, result);
return result;
}
private void traverse(Node node, List<Integer> result) {
if (node == null) return;
result.add(node.val);
for (Node child : node.children) {
traverse(child, result);
}
}
}