Minimum Index Sum of Two Lists
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.
You need to help them find out their common interest with the least list index sum. If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.
Example 1:
Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"]
Output: ["Shogun"]
Explanation: The only restaurant they both like is "Shogun".
Example 2:
Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["KFC", "Shogun", "Burger King"]
Output: ["Shogun"]
Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).
Note:
The length of both lists will be in the range of [1, 1000].
The length of strings in both lists will be in the range of [1, 30].
The index is starting from 0 to the list length minus 1.
No duplicates in both lists.
Here is a solution using hash maps.
class Solution {
public String[] findRestaurant(String[] list1, String[] list2) {
Map<String, Integer> m1 = new HashMap<>();
for (int i = 0; i < list1.length; i++) {
m1.put(list1[i], i);
}
Map<Integer, List<String>> sums = new HashMap<>();
for (int i = 0; i < list2.length; i++) {
String value = list2[i];
if (m1.containsKey(value)) {
Integer position = m1.get(value);
int sum = position + i;
if (!sums.containsKey(sum)) {
sums.put(sum, new ArrayList<>());
}
sums.get(sum).add(value);
}
}
int min = Integer.MAX_VALUE;
for (Integer key : sums.keySet()) {
if (key < min) {
min = key;
}
}
return sums.get(min).toArray(new String[0]);
}
}
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