Given a list ofuniquewords, find all pairs ofdistinctindices(i, j)in the given list, so that the concatenation of the two words, i.e.words[i] + words[j]is a palindrome.
Example 1:
Givenwords=["bat", "tab", "cat"]
Return[[0, 1], [1, 0]]
The palindromes are["battab", "tabbat"]
class Solution {
private static class TrieNode {
TrieNode[] next;
int index;
List<Integer> list;
TrieNode() {
next = new TrieNode[26];
index = -1;
list = new ArrayList<>();
}
}
public List<List<Integer>> palindromePairs(String[] words) {
List<List<Integer>> res = new ArrayList<>();
TrieNode root = new TrieNode();
for (int i = 0; i < words.length; i++) addWord(root, words[i], i);
for (int i = 0; i < words.length; i++) search(words, i, root, res);
return res;
}
private void addWord(TrieNode root, String word, int index) {
for (int i = word.length() - 1; i >= 0; i--) {
int j = word.charAt(i) - 'a';
if (root.next[j] == null) root.next[j] = new TrieNode();
if (isPalindrome(word, 0, i)) root.list.add(index);
root = root.next[j];
}
root.list.add(index);
root.index = index;
}
private void search(String[] words, int i, TrieNode root, List<List<Integer>> res) {
for (int j = 0; j < words[i].length(); j++) {
if (root.index >= 0 && root.index != i && isPalindrome(words[i], j, words[i].length() - 1)) {
res.add(Arrays.asList(i, root.index));
}
root = root.next[words[i].charAt(j) - 'a'];
if (root == null) return;
}
for (int j : root.list) {
if (i == j) continue;
res.add(Arrays.asList(i, j));
}
}
private boolean isPalindrome(String word, int i, int j) {
while (i < j) {
if (word.charAt(i++) != word.charAt(j--)) return false;
}
return true;
}
}